Calculate the volume, amount of substance and mass of hydrogen obtained by the interaction of 80 g of calcium with water.

Ca + 2H2O = Ca (OH) 2 + H2
amount of calcium substance = 80/40 = 2 moles
hence the amount of hydrogen substance is 2 moles
volume 2 * 22.4 = 44.8 liters
weight 2 * 2 = 4 g



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