Calculate the volume and amount of carbon dioxide that is formed when interacting with an excess of nitric

Calculate the volume and amount of carbon dioxide that is formed when interacting with an excess of nitric acid solution 250 g of limestone (calcium carbonate) containing 5% impurities. How many ions of each type are formed as a result of the reaction?

When calcium carbonate reacts with nitric acid, calcium nitrate, water and carbon dioxide gas are synthesized. The reaction is described by the following equation:

CaCO3 + 2HNO3 = Ca (NO3) 2 + CO2 ↑ + H2O;

Determine the chemical amount of calcium carbonate. To do this, divide its weight by its molar mass.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol; N CaCO3 = 250 x 0.95 / 100 = 2.375 mol;

Dissolving this amount of limestone in nitric acid will produce the same amount of carbon dioxide.

Let’s calculate its volume. To this end, we multiply the amount of substance by the volume of 1 mole of gas (filling 22.4 liters).

V CO2 = 2.375 x 22.4 = 53.2 liters;

During the reaction, 2.375 mol of calcium cations and 2.375 x 2 = 4.75 mol of nitro group anions will be obtained in solution.