Calculate the volume and mass of ammonia required to obtain 5 tons of ammonium nitrate.

Let’s calculate the chemical amount of ammonium nitrate. For this purpose, we divide its weight by its molar mass.

M NH4NO3 = 14 + 4 + 14 + 16 x 3 = 80 grams / mol;

N NH4NO3 = 5,000,000 / 80 = 62,500 mol;

This amount of ammonia will be required. Let’s calculate its mass and volume.

Let’s find its volume.

To do this, multiply the amount of substance by the standard volume of 1 mole of gas (which is 22.40 liters)

V NH3 = 62,500 x 22.4 = 1,400,000 liters = 1,400 m3;

Let’s determine its weight.

M NH3 = 14 + 3 = 17 grams / mol;

m NH3 = 62,500 x 17 = 1,062,500 grams = 1.062 tons;