Calculate the volume and mass of carbon dioxide, which is formed when firing 200 kg of limestone containing 15% impurities.

Given:
m mixture (CaCO3) = 200 kg
w approx (CaCO3) = 15%
To find:
V (CO2)
m (CO2)
Decision:
CaCO3 = CO2 + H2O
w is clean. islands (CaCO3) = 100% -15% = 85% = 0.85
m in islands (CaCO3) = w pure. in-va * m mixture = 0.85 * 200 kg = 170 kg = 170,000 g
n (CaCO3) = m / M = 170,000 g / 100 g / mol = 1700 mol
n (CaCO3): n (CO2) = 1: 1
n (CO2) = 1700 mol
V (CO2) = n * Vm = 1700 mol * 22.4 l / mol = 38080 l
m (CO2) = n * M = 1700 mol * 44 g / mol = 74800 g = 74.8 kg
Answer: 38080 l; 74.8 kg