Calculate the volume and mass of oxygen required to obtain 16 g of magnesium oxide.

The reaction of magnesium with oxygen is described by the following chemical reaction equation:

2Mg + O2 = 2MgO;

To obtain two moles of magnesium oxide, one mole of oxygen is needed.

Let’s find the required mass and volume of oxygen. To do this, we first find the amount of substance in 16 grams of magnesium oxide.

M MgO = 24 + 16 = 40 grams / mol;

N MgO = 16/40 = 0.4 mol;

The reaction will enter 0.4 / 2 = 0.2 mol of oxygen.

Under normal conditions, one mole of ideal gas takes up a volume of 22.4 liters.

Determine the volume of oxygen:

V O2 = 0.2 x 22.4 = 4.48 liters;

The molar mass of oxygen is 16 x 2 = 32 grams / mol;

The mass of oxygen will be:

m О2 = 0.2 x 32 = 6.4 grams;