Calculate the volume and number of structural particles in 19 g of nitrogen (IV) oxide.

First, let’s determine the volume of nitrogen oxide. For this we use the following formulas. We write down the solution.
n = m / M.
n = V / Vm.
m / M = V / Vm.
V = Vm × m / M.
M (NO2) = 14 + 2 × 16 = 46 g / mol.
V = 22.4 × 19 ÷ 46 = 9.3 liters.
This means that the volume of nitrogen oxide is 9.3 liters.
Next, we find the amount of nitrogen oxide substance.
n = m / M = 19/46 = 0.41 mol.
This means that the amount of nitrogen oxide substance is 0.41 mol.
Answer: n (NO2) = 0.41 mol; V (NO2) = 9.3 liters.



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