Calculate the volume H released during the interaction, Zn with 300gr. sulfuric acid solution 10% concentration.

univerkov | November 26, 2020 | education

Reaction equation Zn + H2SO4 = ZnSO4 + H2
1) mpure (H2SO4) = W (H2SO4) * m (H2SO4) = 0.1 * 300 = 30g
2) ν (H2SO4) = m (H2SO4) / M (H2SO4) = 30/98 = 0.31 (mol)
3) ν (H2) = ν (H2SO4) = 0.31 (mol)
4) V (H2) = Vm * ν (H2) = 22.4 * 0.31 = 6.944 (l)
Answer: V (H2) = 6.944 liters

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