Calculate the volume (m3) of carbon monoxide (IV) and the mass of burnt lime (CaO)

Calculate the volume (m3) of carbon monoxide (IV) and the mass of burnt lime (CaO) that can be obtained by firing 500 kg of limestone containing 92% calcium carbonate.

The limestone roasting reaction is described by the following equation:

CaCO3 = CaO + CO2 ↑;

When decomposing 1 mol of limestone, 1 mol of calcium oxide and 1 mol of carbon monoxide is obtained.

Let’s calculate the molar amount of calcium carbonate. To do this, divide its weight by its molar weight.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol; N CaCO3 = 500,000 x 0.92 / 100 = 4,600 mol;

Find the weight of 4 600 mol of calcium oxide.

For this purpose, we multiply the amount of the substance by its molar weight.

M CaO = 40 + 16 = 56 grams / mol; m CaO = 4 600 x 56 = 257 600 grams = 257.6 kg;

Let us determine the volume of 4 6000 mol of carbon dioxide.

To do this, multiply the amount of substance by the volume of 1 mole of gas (which is 22.4 liters).

V CO2 = 4 600 x 22.4 = 103 040 liters = 103.04 m3;