Calculate the volume of 98% nitric acid (density 1500 kg / m3) required to obtain 1 ton of

Calculate the volume of 98% nitric acid (density 1500 kg / m3) required to produce 1 ton of trinitrocellulose at 90% yield

Let’s solve this problem using the proportion:

M [C6H7O11N3] n = 1000 kilograms · 0.9 = 900 kilograms (trinitrocellulose).
x kilogram – 900 kilograms;
[C6H10O5] n + 3nHONO2 = [C6H7O11N3] n + 3nH2O;
189 kilograms – 297 kilograms;

x = (189 900) / 297 = 572.7 kilograms;

V (HNO3) = m / ρ = 572.7 / 1500 = 0.382 m³ (volume formula).

Answer: 0.382 m3.