Calculate the volume of a gas mixture consisting of 0.6 mol O2, 0.8 mol H2S, and 0.6 mol CH4?

1. We calculate the chemical amount of a mixture of gases:

n (mixtures) = n (O2) + n (H2S) + n (CH4);

n (mixture) = 0.6 + 0.8 + 0.6 = 2 mol;

2. calculate the volume occupied by the mixture at n. at .:

V (mixture) = n (mixture) * Vm;

V (mixture) = 2 * 22.4 = 44.8 liters.

Answer: 44.8 liters.




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