Calculate the volume of a glucose molecule (nm3) if its density is 1.56 g / cm3. The molecular weight of glucose is 180.16.

1) Find out the mass of one molecule: m0 = MrC6H12O6 / Na, where MrC6H12O6 is the molecular weight of glucose (according to the condition MC6H12O6 = 180.16 g / mol); Na is Avogadro’s number (const, Na = 6.022 * 10 ^ 23 mol-1).

Calculation: m0 = MrC6H12O6 / Na = 180.16 / (6.022 * 10 ^ 23) ≈ 29.917 * 10-23 g.

2) Let’s calculate the volume of the molecule: V0 = m0 / ρC6H12O6, where ρC6H12O6 is the glucose density (according to the condition ρC6H12O6 = 1.56 g / cm3).

Calculation: V0 = m0 / ρC6H12O6 = 29.917 * 10 ^ -23 / 1.56 ≈ 19.18 * 10 ^ -23 cm3 = 19.18 * 10 ^ -29 m3 = 19.18 * 10-20 nm3.

Answer: The volume of a glucose molecule, according to the calculation, is 19.18 * 10 ^ -20 nm3.