Calculate the volume of a solution with a mass fraction of sulfuric acid 10% (density = 1.07 g / cm3)

univerkov | December 30, 2020 | education

Calculate the volume of a solution with a mass fraction of sulfuric acid 10% (density = 1.07 g / cm3), which will be required to neutralize a solution containing 28 g of potassium hydroxide.

2KOH + H2SO4 = K2SO4 + 2H2O
n (KOH) = m (KOH): M (KOH) = 28:56 = 0.5 mol
According to the equation n (H2SO4) = n (KOH): 2 = 0.5: 2 – 0.25 mol
m (H2SO4) = n (H2SO $) * M (H2SO4) = 0.25 * 98 = 24.5 g
m (p-paH2SO4) = m (H2SO4): W (H2SO4) = 24.5: 0.1 = 245 g.

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