Calculate the volume of air required to obtain nitrogen oxide 2 with a volume of 5.6 liters

Given:
V (NO) = 5.6 L
φ (O2) = 21%

To find:
V (air) -?

1) Write the equation of a chemical reaction:
N2 + O2 => 2NO;
2) The air contains less oxygen than nitrogen. Therefore, it is necessary to calculate the volume of oxygen, guided by the Gay-Lussac law (the law of volumetric ratios, taking into account the coefficients in the reaction equation):
V (O2) = V (NO) / 2 = 5.6 / 2 = 2.8 L;
3) Calculate the air volume:
V (air) = V (O2) * 100% / φ (O2) = 2.8 * 100% / 21% = 13.3 liters.

Answer: The air volume is 13.3 liters.