Calculate the volume of ammonia formed by the interaction of 5 liters of hydrogen with nitrogen.

Let’s find the amount of hydrogen substance by the formula:

n = V: Vn.

n = 5 L: 22.4 L / mol = 0.22 mol.

Let’s compose the reaction equation, find the quantitative ratios of substances.

3H2 + N2 = 2NH3

According to the reaction equation, 3 mol of hydrogen accounts for 2 mol of ammonia. Substances are found in quantitative ratios 2: 3 = 1: 1.5.

The amount of ammonia substance will be 1.5 times less than the amount of hydrogen substance.

n (H2) = 2 / 3n (NH3) = 0.22: 1.5 = 0.147 mol.

Let’s find the volume of ammonia.

V = Vn n, where Vn is the molar volume of gas equal to 22.4 l / mol, and n is the amount of substance.

V = 0.147 mol × 22.4 L / mol = 3.29 L.

Answer: 3.29 liters.