Let’s calculate the chemical amount of ammonium chloride. For this purpose, we divide its weight by its molar mass.
M NH4Cl = 14 + 4 + 35.5 = 53.5 grams / mol;
The weight of ammonium chloride will be:
N NH4 Cl = 10.7 / 53.5 = 0.2 mol;
The same amount of ammonia will be synthesized.
Let’s find its volume.
To do this, multiply the amount of substance by the standard volume of 1 mole of gas (which is 22.40 liters)
V NH3 = 0.2 x 22.4 = 4.48 liters;
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