Calculate the volume of ammonia that can be obtained by heating 75 grams of ammonium

| August 14, 2021 | education

Calculate the volume of ammonia that can be obtained by heating 75 grams of ammonium sulfate with an excess of calcium hydroxide if the volume fraction of ammonia yield is 96%

To solve the problem, we will compose an equation, select the coefficients:
(NH4) 2SO4 + Ca (OH) 2 = CaSO4 + 2NH3 + 2H2O – ion exchange reaction, ammonia is released;
Let’s make calculations using the formulas:
M (ammonium sulfate) = 132 g / mol;
Y (ammonium sulfate) = m / M = 75/132 = 0.568 mol (deficient substance);
According to the condition of the problem, Ca (OH) 2 is taken in excess, which means that the calculations are made for the substance in deficiency.
Let’s make the proportion:
0.568 mol (NH4) 2SO4 –X mol (NH3);
-1 mol -2 mol hence, X mol (NH3) = 0.568 * 2/1 = 1.136 mol.
Find the volume of ammonia:
V (NH3) = 1.136 * 22.4 = 25.45 l.
Answer: the volume of ammonia is 25.45 liters.



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