Calculate the volume of ammonia that can be obtained by the interaction of ammonium

Calculate the volume of ammonia that can be obtained by the interaction of ammonium chloride with a mass of 10.7 g and calcium hydroxide with a mass of 8 g.

The mass of ammonium chloride is 10.7 g.

Calcium hydroxide mass – 8 g.

Let’s determine the volume of ammonia obtained during the reaction.

Let’s write down the reaction equation.

2NH4Cl + Ca (OH) 2 = CaCl2 + 2NH3 + 2H2O.

Determine the amount of the substance of ammonium chloride and calcium hydroxide.

M (NH4Cl) = 53 g / mol.

M (Ca (OH) 2) = 74 g / mol.

n = 10.7 / 53 = 0.2 mol.

n = 8/74 = 0.11 mol.

0.2 mol – x mol.

2 mol – 1 mol.

X = 0.1 mol.

We find the volume of ammonia in terms of ammonium chloride.

0.2 mol – at a mol.

2 mol – 2 mol.

Y = 0.2 mol.

V = 0.2 * 22.4 = 4.48 liters.

Answer: 4.48 liters.