Calculate the volume of ammonia that is obtained by heating ammonium chloride weighing 160.5

Calculate the volume of ammonia that is obtained by heating ammonium chloride weighing 160.5 g with an excess of calcium hydroxide.

This reaction proceeds according to the following chemical reaction equation:

2NH4Cl + Ca (OH) 2 = 2NH3 + CaCl2; + 2H2O;

Let’s calculate the chemical amount of ammonium chloride. To do this, we divide its weight by its molar mass.

M NH4Cl = 14 + 4 + 35.5 = 53.5 grams / mol;

The amount of ammonium chloride will be:

N NH4 Cl = 160.5 / 53.5 = 3 mol;

From this amount of salt, it is possible to obtain 3 mol of ammonia.

Let’s calculate its volume.

To this end, we multiply the amount of substance by the standard volume of 1 mole of gas (which is 22.40 liters)

V NH3 = 3 x 22.4 = 67.2 liters;