Calculate the volume of ammonia that is obtained by heating ammonium chloride with a mass

Calculate the volume of ammonia that is obtained by heating ammonium chloride with a mass of 160.5 g with an excess of calcium hydroxide.

Reaction equation: 2NH4Cl + Ca (OH) 2 = CaCl2 + 2NH3 + 2H2O
Let’s find the amount of ammonium chloride substance n = m / M = 160.5 g / 53.5 g / mol = 3 mol. (M – molar mass, determined by the periodic table). According to the reaction from 2 mol of ammonium chloride, 2 mol of ammonia is obtained, which means n (NH4Cl) = n (NH3) = 3 mol. Let’s find the volume of ammonia: V = n * Vm, where Vm = 22.4 l / mol – molar volume (constant for all gases under normal conditions). V (NH3) = 3 mol * 22.4 L / mol = 67.2 L.
Answer: the volume of ammonia is 67.2 liters.