Calculate the volume of carbon dioxide and the mass of water that are formed during the combustion of 86

Calculate the volume of carbon dioxide and the mass of water that are formed during the combustion of 86 grams of hexane C6H14

The combustion reaction of hexane is described by the following chemical reaction equation:

2C6H14 + 19O2 = 12CO2 + 14H2O;

When 2 moles of hexane are burned, 6 moles of carbon dioxide and 7 moles of water are formed.

Let’s find the amount of substance contained in 86 grams of hexane.

M C6H14 = 12 x 6 + 1 x 14 = 86 grams / mol;

N C6H14 = 86/86 = 1 mol;

Find the volume 1 x 6 = 6 moles of carbon dioxide and the mass 1 x 7 = 7 moles of water

Under normal conditions, one mole of ideal gas takes up a volume of 22.4 liters.

Determine the volume of carbon dioxide:

V CO2 = 6 x 22.4 = 134.4 liters;

Let’s find the mass of water by multiplying the amount of a substance by its molar mass, equal to 18 grams / mol:

m H2O = 7 x 18 = 126 grams;