Calculate the volume of carbon dioxide and the mass of water that are formed during the combustion

Calculate the volume of carbon dioxide and the mass of water that are formed during the combustion of 8.6 g of hexane C16H14.

The oxidation reaction of hexane with oxygen is described by the following chemical reaction equation:

2C6H14 + 19O2 = 12CO2 + 14H2O;

19 moles of oxygen are reacted with 2 moles of hexane. This synthesizes 12 mol of carbon monoxide.

Let’s calculate the available chemical amount of hexane.

M C6H14 = 12 x 6 + 14 = 86 grams / mol;

N C6H14 = 8.6 / 86 = 0.1 mol;

This reaction requires 0.1 x 19/2 = 0.95 mol of oxygen.

Let’s calculate the volume of oxygen. To do this, multiply the amount of the substance and the standard volume of 1 mole of the gaseous substance. 1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

V O2 = 0.95 x 22.4 = 21.28 liters;