Calculate the volume of carbon dioxide formed by the interaction of magnesium carbonate in the amount

Calculate the volume of carbon dioxide formed by the interaction of magnesium carbonate in the amount of 0.2 mol with hydrochloric acid. Reaction equation MgCo3 + 2HCl = MgCl + CO2 (arrow up) + H2O

Given: Y (HCl) = 0.2 mol.
Find: V (CO2) -?
Solution:
All calculations are performed in accordance with the reaction equation.
We calculate M (CO2) = 12 + 16 * 2 = 44 g / mol;
Let’s define Y (CO2) according to the reaction equation:
0.2 mol Y (CO2) -?
MgCO3 + 2HCl = MgCl2 + CO2 + H2O;
2 mol 1 mol
Y (HCl) / Y (CO2) = 2/1;
Y (CO2) = 0.2 mol (HCl) * 1/2;
Y (CO2) = 0.1 mol;
Let’s make the proportion:
1 mol СО2 at normal conditions takes V = 22.4 liters;
0.1 mol CO2 – x (l)
X = 22.4 * 0.1 / 1 = 2.24 l;
Answer: V (CO2) = 2.24 l.