Calculate the volume of carbon dioxide generated by the combustion of 66 g of propane?

The propane oxidation reaction is described by the following chemical reaction equation.

C3H8 + 5O2 = 3CO2 + 4H2O;

According to the coefficients of this equation, 5 oxygen molecules are required to oxidize 1 propane molecule. This synthesizes 3 molecules of carbon dioxide.

To do this, divide the available weight of the gas by the weight of 1 mole of this gas.

M C3H8 = 12 x 3 + 8 = 44 grams / mol; N C3H8 = 66/44 = 1.5 mol;

The amount of carbon dioxide will be.

N CO2 = 1.5 x 3 = 4.5 mol;

Let’s calculate the gas volume. To do this, multiply the amount of substance by the volume of 1 mole of gas.

Its volume will be: V CO2 = 4.5 x 22.4 = 100.8 liters;