Calculate the volume of carbon dioxide generated when burning 89.5 g of industrial coal containing 31.2%

| May 18, 2021 | education

Calculate the volume of carbon dioxide generated when burning 89.5 g of industrial coal containing 31.2% of non-combustible impurities, if the volume fraction of the output is 87%.

Let us determine the mass of the combustible part of coal m (C) = m (total) * (1 – w), where m (total) is the mass of technical coal, w is the mass fraction of impurities
m (C) = 89.5 * (1 – 0.312) = 61.576 g
Find the amount of substance n (C) = m (C) / M (C), where M (C) = 12 g / mol is the molar mass.
n (C) = 61.576 / 12 = 5.13 mol
Let’s write the reaction equation:
C + O2 = CO2
It can be seen from the reaction equation that the amount of substance СО2 – n (CO2) = n (C) = 5.13 mol
Find the volume of CO2 – V (CO2) = n (CO2) * Vm, where Vm = 22.4 l / mol – molar volume
V (CO2) = 5.13 * 22.4 = 114.912 L
Taking into account the output ϕ, the obtained practical volume of СО2 – Vpr (СО2) = V (CO2) * ϕ
Vpr (CO2) = 114.912 * 0.87 = 99.97 l



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