Calculate the volume of carbon dioxide obtained by firing 140 g of calcium carbonate containing 2% impurities.

Let us write the equation for the process of calcining calcium carbonate:

CaCO3 = CaO + CO2 – decomposition, carbon dioxide is released;
Let’s make the calculations:
M (CaCO3) = 100 g / mol;

M (CO2) = 44 g / mol;

m (CaCO3) = 140 * (1 – 0.02) = 137.2 g (mass without impurity).

Determine the amount of the original substance:
Y (CaCO3) = m / M = 137.2 / 100 = 1.4 mol;

Y (CO2) = 1.4 mol since the amount of substances is 1 mol.

Find the volume of the product:
V (CO2) = 1.4 * 22.4 = 31.36 L

Answer: received carbon dioxide with a volume of 31.36 liters