Calculate the volume of carbon dioxide obtained by the interaction of 220 g of limestone

Calculate the volume of carbon dioxide obtained by the interaction of 220 g of limestone, the impurity content in it is 10%, with an excess of hydrochloric acid

When calcium carbonate interacts with hydrochloric acid, calcium chloride, water and gaseous carbon dioxide are produced. The reaction proceeds according to the following chemical equation:

CaCO3 + 2HCl = CaCl2 + CO2 ↑ + H2O;

Let’s calculate the molar amount of calcium carbonate. For this purpose, we divide its weight by its molar weight.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol; N CaCO3 = 220 x 0.9 / 100 = 1.98 mol;

When this amount of limestone is dissolved in hydrochloric acid, an equivalent amount of carbon dioxide will be obtained.

Let’s calculate the volume that it occupies. To do this, multiply the amount of substance by the volume of 1 mole of gas (filling 22.4 liters).

V CO2 = 1.98 x 22.4 = 44.352 liters;