Calculate the volume of carbon dioxide produced by combustion of 51.7 g of phenol.

Let’s implement the solution:

According to the condition of the problem, we write down the equation of the process:
С6Н5ОН + 7О2 = 6СО2 + 3Н2О – combustion of phenol, carbon monoxide (4), water are released;

Let’s make the calculations:
M (C6H5OH) = 94 g / mol;

M (CO2) = 44 g / mol;

Y (C6H5OH) = m / M = 51.7 / 94 = 0.6 mol.

Proportion:
0.6 mol (C6H5OH) – X mol (CO2);

-1 mol – 6 mol from here, X mol (CO2) = 0.6 * 6/1 = 3.6 mol.

Find the volume of the product:
V (CO2) = 3.6 * 22.4 = 80.64 L

Answer: received carbon monoxide with a volume of 80.64 liters