Calculate the volume of carbon dioxide released during the decomposition of calcium

Calculate the volume of carbon dioxide released during the decomposition of calcium carbonate weighing 240 grams containing 12% impurities.

The decomposition reaction of limestone is described by the following chemical reaction equation:

CaCO3 = CaO + CO2;

The decomposition of 1 mol of limestone synthesizes 1 mol of gaseous carbon dioxide.

Let’s calculate the available chemical amount of calcium carbonate substance.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

N CaCO3 = 240 x 0.88 / 100 = 2.112 mol;

During the reaction, the same amount of carbon dioxide and carbon dioxide will be synthesized.

Let’s calculate its volume.

To do this, multiply the amount of the substance and the standard volume of 1 mole of the gaseous substance.

1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

V CO2 = 2.112 x 22.4 = 47.31 liters;