Calculate the volume of carbon dioxide released when draining solutions containing 5.3 g

Calculate the volume of carbon dioxide released when draining solutions containing 5.3 g of sodium carbonate and 7.3 g of hydrochloric acid.

Sodium carbonate react with carbon dioxide:
Na2CO3 + 2HCl = 2NaCl + H2O + CO2
The molar mass of Na2CO3 = 106 g, and HCl = 36.5 g, according to the conditions of the problem, 5.3 / 106 = 0.05 mol of salt and 7.3 / 36.5 = 0.2 mol of acid participated in the reaction, i.e. … a two-fold excess, if you look at the coefficients in the reaction equation.
Thus, the reaction will release a volume of carbon dioxide equal to 0.05 mol or 22.4 * 0.05 = 1.12 liters