Calculate the volume of carbon dioxide required to react with 0.05 mol of calcium hydroxide.
August 24, 2021
1. Let us write the equation according to the problem statement:
X l. -? Y = 0.05 mol;
CO2 + Ca (OH) 2 = CaCO3 + H2O – ion exchange reaction, obtained calcium carbonate in the sediment;
2. We make calculations by the formulas:
M (CO2) = 44 g / mol;
M Ca (OH) 2 = 74 g / mol.
3. The amount of starting materials:
Y Ca (OH) 2 = 0.05 mol (equation data);
Y (CO2) = 0.05 mol since the amount of these substances is equal to 1 mol according to the equation.
4. Find the volume of the original substance:
V (CO2) = 0.05 * 22.4 = 1.12 liters.
Answer: to carry out the process, carbon monoxide with a volume of 1.12 liters is required.
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