Calculate the volume of carbon dioxide that can be formed during alcoholic fermentation of a solution containing 720 g of glucose.
Let’s execute the solution:
1. In accordance with the condition of the problem, we write the equation:
m = 720 g. X l. -?
С6Н12О6 = 2СО2 + 2С2Н5ОН – alcoholic fermentation occurs with the participation of yeast, carbon dioxide and ethanol are released;
2. Calculations by formulas:
M (C6H12O6) = 180 g / mol;
M (CO2) = 44 g / mol;
Y (C6H12O6) = m / M = 720/180 = 4 mol.
4 mol (C6H12O6) – X mol (CO2);
-1 mol -2 mol from here, X mol (CO2) = 4 * 2/1 = 8 mol.
4. Find the volume of CO2:
V (CO2) = 8 * 22.4 = 179.2 liters.
Answer: received carbon monoxide (4) with a volume of 179.2 liters.
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