Calculate the volume of carbon dioxide that can be formed during alcoholic fermentation of a solution

| February 7, 2021 | education

Calculate the volume of carbon dioxide that can be formed during alcoholic fermentation of a solution containing 720 g of glucose. Calculate the mass of 96% ethyl alcohol that can be obtained as a result of this reaction with a product yield equal to 85% of the theoretically possible.

Given:
m (C6H12O6) = 720 g
ω (C2H5OH) = 96%
η (C2H5OH) = 85%

To find:
V (CO2) -?
m solution practical (C2H5OH) -?

1) C6H12O6 => 2C2H5OH + 2CO2 ↑;
2) n (C6H12O6) = m / M = 720/180 = 4 mol;
3) n (CO2) = n (C6H12O6) * 2 = 4 * 2 = 8 mol;
4) V (CO2) = n * Vm = 8 * 22.4 = 179.2 l;
5) n theory. (C2H5OH) = n (C6H12O6) * 2 = 4 * 2 = 8 mol;
6) n practical (C2H5OH) = η * n theory. / 100% = 85% * 8/100% = 6.8 mol;
7) m practical. (C2H5OH) = n practical. * M = 6.8 * 46 = 312.8 g;
8) m solution practical. (C2H5OH) = m practical. * 100% / ω = 312.8 * 100% / 96% = 325.8 g.

Answer: The CO2 volume is 179.2 liters; the mass of the C2H5OH solution is 325.8 g.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.