Calculate the volume of carbon dioxide that forms with a solution of 300 grams of chalk containing 30

Calculate the volume of carbon dioxide that forms with a solution of 300 grams of chalk containing 30 percent impurities in hydrochloric acid.

The reaction of interaction of calcium carbonate with hydrochloric acid is described by the following chemical reaction equation:

CaCO3 + 2HCl = CaCl2 + H2O + CO2;

The reaction of one mole of calcium carbonate produces one mole of carbon monoxide.

Let’s find the mass and amount of the calcium carbonate substance:

m CaCO3 = 300 x (1 – 30%) = 210 grams;

Determine the amount of substance in 210 grams of calcium carbonate.

Its molar mass is:

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

The amount of substance will be:

N CaCO3 = 210/100 = 2.1 mol;

The same amount of carbon monoxide will be obtained.

Under normal conditions, one mole of ideal gas takes up a volume of 22.4 liters.

Let’s determine the volume of carbon dioxide:

V CO2 = 2.1 x 22.4 = 47.04 liters;