Calculate the volume of carbon dioxide that is emitted when burning 500 m3 of natural

Calculate the volume of carbon dioxide that is emitted when burning 500 m3 of natural gas containing 98% methane.

The oxidation reaction of methane with oxygen is described by the following chemical reaction equation:

CH4 + 3O2 = CO2 + 2H2O;

1 mol of gas is reacted with 2 mol of oxygen. 1 mole of carbon dioxide is synthesized.

Let’s calculate the available chemical amount of methane. 1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

N CH4 = 500,000 x 0.98 / 22.4 = 21,875 mol;

When such an amount of matter is burned, 21,875 moles of carbon dioxide will be released.

Let’s calculate its volume. To do this, multiply the amount of the substance and the standard volume of 1 mole of the gaseous substance. 1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

V CO2 = 21,875 x 22.4 = 490,000 liters = 490 m3;