Calculate the volume of carbon dioxide that is formed by the interaction of 300 grams of calcium

Calculate the volume of carbon dioxide that is formed by the interaction of 300 grams of calcium carbonate with hydrochloric acid?

The dissolution reaction of limestone in hydrochloric acid is described by the following chemical reaction equation:

CaCO3 + 2HCl = CaCl2 + CO2 + H2O;

When 1 mol of limestone is dissolved in acid, 1 mol of gaseous carbon dioxide is synthesized. This consumes 2 mol of hydrochloric acid.

Let’s calculate the available chemical amount of calcium carbonate substance.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

N CaCO3 = 300/100 = 3 mol;

Thus, upon dissolution of 3 mol of limestone, 3 mol of carbon dioxide is synthesized. This will require 6 moles of acid.

Let’s calculate the gas volume. To do this, multiply the amount of the substance and the standard volume of 1 mole of the gaseous substance. 1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

V CO2 = 3 x 22.4 = 67.2 liters;