Calculate the volume of carbon dioxide that is formed during the combustion of methanol (methanol) weighing 0.56 g.

The oxidation reaction of methanol with oxygen is described by the following chemical reaction equation:

CH3OH + 2O2 = CO2 + 2H2O;

1 mol of alcohol is reacted with 2 mol of oxygen.

Let’s calculate the available chemical amount of the alcohol substance.

M CH3OH = 12 +16 + 4 = 32 grams / mol;

N CH3OH = 0.56 / 32 = 0.018 mol;

When such an amount of matter is burned, 0.018 mol of carbon dioxide will be released.

Let’s calculate its volume by multiplying the amount of the substance by the volume of 1 mole of the substance.

V O2 = 0.018 x 22.4 = 0.403 liters;

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