Calculate the volume of carbon dioxide that is formed when 250 g of limestone containing 20%

Calculate the volume of carbon dioxide that is formed when 250 g of limestone containing 20% impurities is dissolved in acetic acid.

When calcium carbonate reacts with acetic acid, calcium acetate, water and gaseous carbon dioxide are produced. The reaction proceeds according to the following chemical equation:

CaCO3 + 2CH3COOH = Ca (CH3COO) 2 + CO2 ↑ + H2O;

Let’s calculate the molar amount of calcium carbonate. To do this, divide its weight by its molar weight.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol; N CaCO3 = 250 x 0.8 / 100 = 2 mol;

By dissolving this amount of limestone in acetic acid, an equivalent amount of carbon dioxide will be obtained.

Let’s find the volume that it occupies. For this purpose, we multiply the amount of substance by the volume of 1 mole of gas (which is 22.4 liters).

V CO2 = 2 x 22.4 = 44.8 liters;