Calculate the volume of carbon dioxide that is formed when coal weighing 9 kg is burned in excess of oxygen.

1.Let’s find the amount of carbon by the formula:

n = m: M.

M (C) = 12 kg / kmol.

n = 9 kg: 12 kg / kmol = 0.75 kmol.

C + O2 = CO2.

1 kmol of carbon accounts for 1 kmol of carbon dioxide. They are in quantitative ratios of 1: 1. The amount of carbon and oxygen will be the same.

n (CO2) = 0.75 kg / kmol.

Let’s find the volume of carbon dioxide.

V = Vn n, where Vn is the molar volume of the gas, equal to 22.4 l / mol, and n is the amount of substance.

V = 22.4 l / kmol × 0.75 kmol = 16.8 m3.

Answer: 16.8 m3.