Calculate the volume of carbon dioxide that is released during the combustion of 10 liters of acetylene.

The oxidation reaction of acetylene is described by the following chemical reaction equation.
C2H2 + 5/2 O2 = 2CO2 + H2O;
According to the coefficients of this equation, 2.5 oxygen molecules are required to oxidize 1 acetylene molecule. This synthesizes 2 molecules of carbon dioxide.
The molar volume of the gas is standard and under normal conditions it fills a volume of 22.4 liters.
Since the molar volume of the gas is standard, double the amount of carbon dioxide will require twice the volume.
The required volume of carbon dioxide is 10 x 2 = 20 liters.



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