Calculate the volume of carbon dioxide that is released during the fermentation of glucose

| June 19, 2021 | education

Calculate the volume of carbon dioxide that is released during the fermentation of glucose, if the mass of the ethanol obtained is 6, 9 grams. As well as a lot of glucose.

Let us write the equation for the reaction of alcoholic fermentation of glucose.

C6H12O6 = 2C2H5OH + 2CO2

Let us find the number of moles of ethanol, knowing its mass (6.9 g).

n (C2H5OH) = m / M = 6.9 / 46 = 0.15 mol.

According to the reaction equation, from 1 mol of glucose, 2 mol of ethanol and carbon dioxide are obtained. From x mol of glucose, 0.15 mol of ethanol is obtained. Let’s make a proportion.

1 mol glucose – 2 mol ethanol

x mol of glucose – 0.15 mol of ethanol

x (C6H12O6) = 0.075 mol

n (C2H5OH) = n (CO2) = 0.15 mol.

Let’s calculate the amount of CO2 generated under normal conditions.

V (CO2) = n * Vm = 0.15 * 22.4 = 3.36 liters.

Let’s calculate the mass of glucose.

m (C6H12O6) = n * M = 0.075 * 180 = 13.5 g



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