# Calculate the volume of carbon dioxide that will be released during the decomposition of 50 grams of calcium carbonate.

The decomposition reaction of limestone is described by the following chemical reaction equation:

CaCO3 = CaO + CO2;

When 1 mol of limestone is decomposed, 1 mol of gaseous carbon dioxide is synthesized.

Let’s calculate the available chemical amount of calcium carbonate substance.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

N CaCO3 = 50/100 = 0.5 mol;

During the reaction, the same amount of carbon dioxide and calcium oxide will be synthesized.

Let’s calculate the volume of carbon dioxide. To do this, multiply the amount of the substance and the standard volume of 1 mole of the gaseous substance.

1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

V CO2 = 0.5 x 22.4 = 11.2 liters;

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