Calculate the volume of carbon dioxide that will be released when 0.5 mol of sodium carbonate

Calculate the volume of carbon dioxide that will be released when 0.5 mol of sodium carbonate reacts with an excess of acetic acid.

The reaction of sodium carbonate with acetic acid is described by the following chemical reaction equation:

Na2CO3 + 2 CH3COOH = 2 CH3COONa + CO2 + H2O;

From one mole of sodium carbonate, one mole of carbon dioxide is formed.

The amount of carbon dioxide is 0.5 mol.

Under normal conditions, one mole of ideal gas takes up a volume of 22.4 liters.

The volume of carbon dioxide will be:

V CO2 = 0.5 x 22.4 = 11.2 liters;