Calculate the volume of carbon dioxide that will be released when 10.6 g of sodium carbonate reacts with chloride acid.

1.Let’s find the amount of sodium carbonate substance by the formula:

n = m: M.

M (Na2CO3) = 23 × 2 + 12 + 16 × 3 = 106 g / mol.

n = 10.6 g: 106 g / mol = 0.1 mol.

2. Let’s compose the reaction equation, find the quantitative ratios of substances.

Na2CO3 + 2HCl = 2NaCl + CO2 ↑ + H2O.

According to the reaction equation, 1 mol of sodium carbonate accounts for 1 mol of carbon dioxide. Substances are in quantitative ratios of 1: 1.

The amount of substance will be the same.

n (Na2CO3) = n (CO2) = 0.1 mol.

3.Let’s find the volume of carbon dioxide by the formula:

V = Vn n, where Vn is the molar volume of gas, equal to 22.4 l / mol, and n is the amount of substance.

V = 22.4 L / mol × 0.1 mol = 2.24 L.

Answer: 2.24 liters.