Calculate the volume of carbon dioxide that will be released when 145 g of 35%

| July 2, 2021 | education

Calculate the volume of carbon dioxide that will be released when 145 g of 35% sodium carbonate solution interacts with hydrochloric acid solution.

First, we write down the equation of reactions.
Na2CO3 + 2 HCL -> 2NaCl + H2O + CO2.
Next, we find the mass of sodium carbonate. We use the following formula.
W = m r.v / mr-ra × 100%.
m (Na2CO3) = m solution × W / 100% = 145 × 35/100 = 50.75 g NaCl.
Next, we find the amount of sodium carbonate substance. For this we use the following formula.
n = m / M.
M (Na2CO3) = 23 × 2 + 12 + 3 × 16 = 106 g / mol.
n = 50.75 / 106 = 0.48 mol.
Further, according to the reaction equation, we find the amount of carbon dioxide.
0.48 mol Na2CO3 – х mol СО2
1 mol NA2CO3 – 1 mol CO2
x = 0.48 × 1 ÷ 1 = 0.48 mol of CO2.
Find the volume of CO2.
n = V / Vm.
V = n × Vm = 0.48 × 22.4 = 10.7 liters of CO2.
Answer: V (CO2) = 10.7 liters.



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