Calculate the volume of carbon dioxide that will evolve at 159 g of sodium carbonate with hydrochloric acid.

The reaction of dissolving sodium carbonate in hydrochloric acid is described by the following chemical reaction equation:

Na2CO3 + 2HCl = 2NaCl + CO2 + H2O;

When 1 mol of sodium carbonate is dissolved in acid, 1 mol of gaseous carbon dioxide is synthesized. This consumes 2 mol of hydrochloric acid.

Let’s calculate the chemical amount of a substance contained in 159 grams of sodium carbonate.

M Na2CO3 = 23 x 2 + 12 + 16 x 3 = 106 grams / mol;

N Na2CO3 = 159/106 = 1.5 mol;

Thus, taking into account the yield of 100% when dissolving 1.5 mol of soda, 1.5 mol of carbon dioxide is synthesized.

Let’s calculate its volume. To do this, multiply the amount of substance and the standard volume of 1 mole of gaseous substance. 1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

V CO2 = 1.5 x 22.4 = 33.6 liters;