Calculate the volume of carbon dioxide under normal conditions, which is formed by the combustion

Calculate the volume of carbon dioxide under normal conditions, which is formed by the combustion of 300 liters of propane.

The oxidation reaction of propane with oxygen is described by the following chemical reaction equation:

C3H8 + 5O2 = 3CO2 + 4H2O;

1 mol of gas is reacted with 5 mol of oxygen. 3 moles of carbon dioxide are synthesized.

Let’s calculate the available chemical amount of propane. 1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

N C3H8 = 300 / 22.4 = 13.39 mol;

This will release 13.39 x 3 = 40.17 mol of carbon dioxide.

Let’s calculate its volume by multiplying the amount of the substance by the volume of 1 mol of the gaseous substance.

V CO2 = 40.17 x 22.4 = 899.81 liters;