Calculate the volume of carbon (IV) oxide formed by heating magnesium carbonate weighing 8.4 kg.

The decomposition reaction of magnesium carbonate is described by the following chemical reaction equation:

MgCO3 = MgO + CO2;

Upon decomposition of 1 mol of magnesium carbonate, 1 mol of gaseous carbon dioxide and 1 mol of magnesium oxide are synthesized.

Let’s calculate the available chemical amount of calcium carbonate substance.

M MgCO3 = 24 + 12 + 16 x 3 = 84 grams / mol;

N MgCO3 = 8 400/84 = 100 mol;

During the reaction, the same amount of carbon dioxide and carbon dioxide will be synthesized. Let’s calculate its volume. To do this, multiply the amount of the substance and the standard volume of 1 mole of the gaseous substance.

1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

V CO2 = 100 x 22.4 = 22 400 liters = 22.4 m3;