Calculate the volume of carbon monoxide 4 produced by adding 50 g of calcium carbonate.

The reaction equation for the thermal decomposition of calcium carbonate:

CaCO3 (t) = CaO + CO2

Amount of calcium carbonate substance:

v (CaCO3) = m (CaCO3) / M (CaCO3) = 50/100 = 0.5 (mol).

According to the reaction equation, from 1 mol of CaCO3, 1 mol of CO2 is formed, therefore:

v (CO2) = v (CaCO3) = 0.5 (mol).

Thus, the volume of carbon dioxide measured under normal conditions (n.o.):

V (CO2) = v (CO2) * Vm = 0.5 * 22.4 = 11.2 (l).

Answer: 11.2 (l).