Calculate the volume of carbon monoxide (4) released during the calcination of 1 kg

Calculate the volume of carbon monoxide (4) released during the calcination of 1 kg of chalk, the mass fraction of polluting sand in which is 15%

Reaction equation:
CaCO3 = CaO + CO2
Since we have 15% sand, then the remaining 85% is carbonate, we actually need it
Let’s calculate the mass of carbonate:
m = w * m (chalk) = 0.85 * 1kg = 0.85kg or 850g
Let’s calculate the amount of calcium carbonate substance:
n = m / M = 0.85kg / 100kg / kmol = 0.0085 kmol
According to the reaction equation:
n (CO2) = n (CaCO3) = 0.0085 kmol
Let’s calculate the volume:
V = Vm * n = 0.0085 kmol * 22.4m³ / kmol = 0.1904m³ or 190.4 liters