Calculate the volume of carbon monoxide (4), which can be obtained from 2.5 kg of limestone, in which 80% calcium carbonate

Calculate the volume of carbon monoxide (4), which can be obtained from 2.5 kg of limestone, in which 80% calcium carbonate. What is the mass of waste rock (impurities) in the limestone sample taken?

The decomposition reaction of limestone is described by the following chemical reaction equation:

CaCO3 = CaO + CO2;

When 1 mol of limestone is decomposed, 1 mol of gaseous carbon dioxide is synthesized.

Let’s calculate the available chemical amount of calcium carbonate substance.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

N CaCO3 = 2,500 x 0.8 / 100 = 20 mol;

The impurity weight will be 2500 x 0.2 = 500 grams;

During the reaction, the same amount of carbon dioxide will be synthesized.

Let’s calculate its volume. To do this, multiply the amount of the substance and the standard volume of 1 mole of the gaseous substance.

1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

V CO2 = 20 x 22.4 = 448 liters;